4p^2-7p-2=0

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Solution for 4p^2-7p-2=0 equation: 



4p^2-7p-2=0

a = 4; b = -7; c = -2;
Δ = b2-4ac
Δ = -72-4·4·(-2)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-9}{2*4}=\frac{-2}{8}
=-1/4
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+9}{2*4}=\frac{16}{8}
=2
$

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